Min Stack
Two way : Use stack or use linkedlist with node
[x] ##### Min Stack这个题目,用了Node,这个思想很厉害!!!!
[x] ##### 用Node, 通过一个linked list of nodes, 完成remove 操作,用head一直指向栈顶,
[x] ##### 并且用一个min永远保存当前最小的min!!!!
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); -->Returns -3.
minStack.pop();
minStack.top(); ->Returns 0.
minStack.getMin(); -->Returns -2.//-3已经被pop出去了。怎么更新min value in stack
class MinStack {
/** initialize your data structure here. */
private Node head;
public MinStack() {
}
public void push(int x) {
if (head == null) {
head = new Node(x, x);
}else{
head = new Node(x, Math.min(x, head.min), head);
}
}
public void pop() {
head = head.next;
}
public int top() {
return head.val;
}
public int getMin() {
return head.min;
}
private class Node{
int val;
int min;
Node next;
private Node(int val, int min) {
this(val, min, null);
}
private Node(int val, int min, Node next) {
this.val = val;
this.min = min;
this.next = next;
}
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
Stack:
public class MinStack {
/** initialize your data structure here. */
/**
* 155. Min Stack
* Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> Returns -3.
minStack.pop();
minStack.top(); --> Returns 0.
minStack.getMin(); --> Returns -2.
在-128~127的Integer值并且以Integer x = value;的方式赋值的Integer值在进行==和equals比较时,都会返回true,
因为Java里面对处在在-128~127之间的Integer值,用的是原生数据类型int,会在内存里供重用,
也就是说这之间的Integer值进行==比较时只是进行int原生数据类型的数值比较,而超出-128~127的范围,进行==比较时是进行地址及数值比较
time : O(1)
space : O(n)
*/
private Stack<Integer> stack;
private Stack<Integer> minStack;
public MinStack() {
stack = new Stack<>();
minStack = new Stack<>();
}
public void push(int x) {
stack.push(x);
if (!minStack.isEmpty()) {
int min = minStack.peek();
if (x <= min) {
minStack.push(x);
}
} else {
minStack.push(x);
}
}
public void pop() {
int x = stack.pop();
if (!minStack.isEmpty()) {
if (x == minStack.peek()) {
minStack.pop();
}
}
}
public int top() {
return stack.peek();
}
public int getMin() {
return minStack.peek();
}
}
class MinStack2 {
/**
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> Returns -3.
minStack.pop();
minStack.top(); --> Returns 0.
minStack.getMin(); --> Returns -2.
*/
Stack<Integer> stack;
int min;
public MinStack2() {
stack = new Stack<>();
min = Integer.MAX_VALUE;
}
public void push(int x) {
if (x <= min) {
stack.push(min);
min = x;
}
stack.push(x);
}
public void pop() {
if (stack.pop() == min) {
min = stack.pop();
}
}
public int top() {
return stack.peek();
}
public int getMin() {
return min;
}
}